If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k^2=-6-7k
We move all terms to the left:
k^2-(-6-7k)=0
We add all the numbers together, and all the variables
k^2-(-7k-6)=0
We get rid of parentheses
k^2+7k+6=0
a = 1; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·1·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*1}=\frac{-12}{2} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*1}=\frac{-2}{2} =-1 $
| p-6+8p=12 | | 175=25-20x | | .1875=k.25 | | -1.56=1+y/2 | | 2x+36=49 | | 65x-12+43x+10=90 | | 7+5x=7.5 | | -8n+7n=-4 | | 175=-25x20 | | 225=k25 | | -14(z-5)=-14+70 | | -1-X-8=25x-7(5x-8) | | 3/4(12x+8)=9x+-2 | | 175=-2520x | | (5x+1)=(8x-32) | | 6-x=-x+6 | | (x-6/2)+(6/2)=(x/7) | | 0=-7v-2v | | 6-x=-x | | X=-5y+40 | | -9x=5/7=7/9 | | 5+4x-x=8 | | 1=x/25 | | 9u-30=5u=6 | | (6x-11)+(7x+10)=90 | | .05x+.1(3x)=63.45 | | 2(6x+9)=5(7x+10) | | -6u-16=8(u+5) | | 29=x/3 | | x-28+7x-24=180 | | -7y+5(y-2)=-28 | | 7/3=3x-2 |